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The expression for thermo emf in a therm...

The expression for thermo emf in a thermocouple given by the relation `E=40theta-(theta^(2))/(20)`, where `theta` is the temperatue difference of two junctons. For this, the neutral temperature will be

A

`100^@C`

B

`200^@C`

C

`300^@C`

D

`400^@C`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = 40 theta -(theta^2)/(20)`
For neutral temperature.
`(dE)/(d theta) = 40-(theta)/(10)=0 implies theta = 400^(@)C`.
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