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If E=at+bt^(2), what is the neutral temp...

If `E=at+bt^(2)`, what is the neutral temperature

A

`-(a)/(2b)`

B

`+(a)/(2b)`

C

`-(a)/(b)`

D

`+(a)/(b)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = a t + bt^(2)`
For netual temperature
`(dE)/(dt) = a.1+b . 2t = 0`
`t = -(a)/(2b)`.
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