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If nearly 10^(5) coulomb liberate 1 g eq...

If nearly `10^(5)` coulomb liberate `1 g` equivalent of aluminium, then the amount of aluminium (equivalent weight `9`) deposited through electrolysis in `20` minutes by a current of `50` amp will be

A

0.06g

B

0.09g

C

5.4g

D

10.8g

Text Solution

Verified by Experts

The correct Answer is:
C
`m = Z` it
`(m_1)/(m_2) = (i_1t_1)/(V_2t_2) implies 9/(m_2) = (10^5)/(50xx20xx60) implies m_(2) = 5.4g`.
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