A circuit consisting of a capacitor and an active resistance `R=110 Omega` connected in series is fed an alternating voltage with amplitude `V_(m)=110V`. In this case the amplitude of steady `-` state current is equal to `I_(m)=0.50 A`. Find the phase difference between the current and the voltage fed.

Explanation

`i_(0) =0.50 A`
`i_(0) = (V_(0))/(Z) implies 0.5 = (110)/(Z) implies Z = 220 Omega`
`Z^(2) = R^(2) + X_(c)^(2) implies (220)^(2) = (110)^(2) + X_(C)^(2)`
`X_(C)^(2) = (220)^(2) -(110)^(2) = 330 xx 110`
`X_(C) = 110sqrt3Omega`
`tan phi = (X_(C))/(R) = (110sqrt3)/(110) = sqrt3`
`phi =60^(@)`
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