An `L-C-R` series circuit with `100Omega` resistance is connected to an `AC` source of `200V` and angular frequency `300rad//s`. When only the capacitance is removed, the current lags behind the voltage by `60^@`. When only the inductance is removed the current leads the voltage by `60^@`. Calculate the current and the power dissipated in the `L-C-R` circuit

Explanation

When capacitance is removed I e `R -L` circuit
`tan 60^(@) = (X_(L))/R implies X_(L) = sqrt3 R`
`X_(L) =X_(C)` circuit is at resonance
Impedance of circuit `Z =R = 100 Omega`
`i_(rms) = V_(rms)/(Z) =(200)/(100) =2A`
`P = i^(2) R = (2)^(2) xx 100 =400W`
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