In a series `RC` circuit with an AC source, `R = 300 Omega, C = 25 muF, epsilon_0= 50 V` and `v = 50/(pi) Hz`. Find the peak current and the average power dissipated in the circuit.

Explanation

`X_(C) = (1)/(omegaC) = (1)/(2pi f C) = (1)/(2pi xx (5)/(pi) xx 25 xx 10^(-2)) = 400 Omega`
`Z = sqrt(R^(2) + X_(C)^(2)) = sqrt ((300)^(2) + (400)^(2)) = 500 Omega`
`i_(0) = (V_(0))/(Z) = (50)/(500) = 0.1 A`
`cos phi = (R )/(Z) = (300)/(500) = (3)/(5)`
`p = (1)/(2) V_(0)i_(0) cos phi`
`= (1)/(2) xx 50 xx 0.1 xx (3)/(5)`
`= 1 .5 W` ltBRgt .