Determine the impedance of the circuit phase of current
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Explanation

`i_(R) =V//R` in phase with vlotage
`i_(L) = V//X_(L)` lags voltage by `pi//2`
`i_(C) = V//X_(C)` leads voltage by `pi //2`
Assuming `i_(C gti_(L)`
Resultant courrent: `I = [i_(R)^(2) + (i_(C) - i_(L))^(2)]^(1/2)`
`(V)/(Z) = [((V)/(R))^(2) + ((V)/(X_(C)) - (V)/(X_(L)))^(2)]^(1/2)`
` (1)/(Z)v = [(1)/(R^(2)) + (1/(X_(C)) - (1)/(X_(L)))^()]^(1/2)`
Impedance` Z = [(1)/(R^(2))+ (omegaC -(1)/(omegaL))^(2)]^(1/(2))`
phase difference : `tan phi = (i_(C) -i_(L))/(iR) = ((1)/(X_(C)) - (1)/(X_(L)))/(1//R)`
`phi = tan^(-1) [R (omegaC-(1)/(omegaL))]`
Current leads
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