The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be

Options

A. `2 xx 10^(-2)` and `14 .14` amp
B. `1 xx 10^(-2)` and `7 .07` amp
C. `5 xx 10^(-3)` and `7.07`amp
D. `5xx10^(3)` and `14.14`amp

Answer

D

Explanation

`f = 50 Hz, T = (1)/(f) = (1)/(50) = 0.02 sec`
Time taken by current from `I = 0` to `I = i_(0)` is
`(T)/(4) = (0.02)/(4) = 5xx 10^(-3)` sec
`i_(0) = sqrt2 i_(rms) = 10sqrt2 = 10 xx 1.41 =14.1 A`
.