An AC source is rated `220 V, 50 Hz`. The average voltage is calculated in a time interval of `0.01 s`. It

Options

A. must be zero
B. may be zero
C. is never zero
D. is `200//sqrt2V`

Answer

B

Explanation

`f = 50 Hz, T = (1)/(f) = (1)/(50) =0.02 sec`
if `t =0 to t = (T)/(2) bar(V) = 0`
`if t = (T)/(4) to t = (3T)/(4) bar V =0` .