An alternating voltage is connected in series with a resistance `R` and inductance `L` if the potential drop across the resistance is `200V` and across the inductance is `150V`, then the applied voltage is

Options

A. `350V`
B. `350 sqrt2V`
C. `250V`
D. `250 sqrt2V`

Answer

C

Explanation

`V^(2) = V_(R)^(2) + V_(C)^(2) = (200)^(2) + (150)^(2) + (150)^(2) = (250)^(2)`
`V =250 V` .