An ideal inductor of `(1//pi)` is connected in series with a `300gamma` resistor If a `20V.200H_(z)` ac source is connected across the combination the phase difference between the voltage and the current is .

Options

A. `tan^(-5)/(4)`
B. `ta n-^(1)4/5`
C. `ta n-^(1)3/4`
D. `ta n-^(1)4/3`

Answer

D

Explanation

`f = 200 Hz , omega = 2pi f = 400 pi rad//sec`
`X_(L) = omegaL = 400 pi xx (1)/(pi) = 400 Omega`
`tan phi = X_(l)/R = (400)/(300) implies phi =tan^(-1) ((4)/(3))` .