When an ac source of emf`e=E_(0) sin (100 t)` is connected across a circuit, the phase difference between emf e and currnet I in the circuit is observed to be `(pi)//(4)` as shown in fig. If the circuit consists possibly only of R-C or R-C of L-R series, find the relationship find the relationship between the two elements.

Options

A. `R = 1 kOmega, C = 10mF`
B. `R = 1 kOmega, C = 1mF`
C. `R = 1 kOmega, L = 10mF`
D. `R = 1 kOmega, L = 1H`

Answer

A

Explanation

`e = E_(0) sin (100 t) =E_(0) sin omega t`
`omega = 100 rad//sec`
`phi = (pi)/(4)` is possible in `RC` not in `LC`
`tan phi = X_(C)/(R) implies (tan) ((pi)/(4)) = (1 //omegaC)/(R)`
`RC = (1)/(omega) = (1)/(100)` .