An LCR series circuit containing resistance of `20omega` has angular resonat frequency `4 xx 10^(5)ms^(-1)` At resonance the voltage across resistance and inductance are `600V` and `40V` respectively The values of `L` and `C` are .

Options

A. `0.2 mH, (1)/(32) muF`
B. `0.4 mH, (1)/(16) muF`
C. `0.2 mH, (1)/(16) muF`
D. `0.4 mH, (1)/(16) muF`

Answer

A

Explanation

`R = 120 Omega, omega_(r) = 4 xx 10^(5) rad//sec, V_(R) =60 V, V_(L) =40 V`
`V_(L) = iX_(L) implies 60 = I xx 120 implies I = (1)/(2)A`
`V_(L) = iX_(L) implies 40 = (1)/(2) X_(L) implies X_(L) =80 Omega`
`omega_(r) L =80 implies 4 xx 10^(5) L =80`
`L = 20 xx 10^(-5) H = 0.2 mH`
`X_(c) = X_(L) =80 implies (1)/(omega ,C) =80`
`C = (1)/(80 omega) = (1)/(80 xx 4 xx 10^(5)) = (10^(-6))/(32) = (1)/(32) muF` .