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Power dissipated in an L-C-R series circ...

Power dissipated in an `L-C-R` series circuit connected to an `AC` source of emf `epsilon` is

A

`(E^(2)R)/[[R^(2) + (Lomega - (1)/(Comega))^(2)]`

B

`(E^(2) sqrt(R^(2) + (Lomega - (1)/(Comega))^(2)))/R`

C

`(E^(2) [R^(2) + (Lomega - (1)/(Comega))^(2)])/R `

D

`(E^(2)R)/(sqrt(R^(2) + (Lomega (1)/(Comega))^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A

`P = V_(rms) I_(rms) cos phi = V_(rms) V_(rms)/(Z) R /(Z)`
`(V_(rms)^(2)R)/(Z^(2)) = (E^(2)R)/(R^(2) + (Lomega- (1)/(Comega))^(2))` .
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