An ac source is connected across a resistance of `10 Omega` The power dissipated in the resistor is `100W` The rms valuse of the current and voltge are .

Options

A. `sqrt10 A ,sqrt(1000)V`
B. `2 sqrt(10) A ,2 sqrt(1000)V`
C. `2 sqrt(10) A, 2sqrt(1000)V`
D. `sqrt(10) A , 2sqrt(1000) V`

Answer

A

Explanation

`P = i^(2)_(rms) R implies 100 i^(2) _(rms) xx 10`
`i_(rms) = sqrt10A`
`V_(rms) = i_(rms) R =10 sqrt10 = sqrt(1000)V` .