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If 5% of the energy supplied to a bulb is irradiated as visible light, how many quanta are emitted per second by a 100 W lamp? Assume wavelength of visible light as `5.6xx10^(-5)` cm.

A

`1.4xx10^(19)`

B

`1.4xx10^(20)`

C

`2xx10^(19)`

D

`2xx10^(20)`

Text Solution

Verified by Experts

The correct Answer is:
A

`P=(5)/(100)xx100=5W`
`P=n(hc)/(lambda)`
`n=(P lambda)/(hc) =(5xx5.6xx10^(-7))/(6.6xx10^(-34)xx3xx10^(8)) =1.4xx10^(19)//sec`
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