In question 23, if the intensity of light is made 4 I, the saturation current will become

Options

A. `0.4 mu A`
B. `0.4xx2 mu A`
C. `1.6 mu A`
D. `0.4xx16 mu A`

Answer

C

Explanation

Saturation current `prop` intensity
`(i_(2))/(0.40) =(4 I)/(I) =4`
`(i_(2))/(i_(1)) =4` `implies i_(2) =1.6 mu A`