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An electron of mass me and a proton of m...

An electron of mass `m_e` and a proton of mass `m_p` are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

A

`1`

B

`(m_(e))/(m_(p))`

C

`(m_(p))/(m_(e))`

D

`sqrt((m_(p))/(m_(e)))`

Text Solution

Verified by Experts

The correct Answer is:
D

NA
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