(i) calculate the value of output voltage `V_(0)` and current `I` if silicon diode and germanium diode conduct at `0.7V` and `0.3 V` respectively. Fig.

(ii) If now germanium diode is cinnected to `12 V` in reverse polarity, find new values of `V_(0)` and `I`.

Explanation

As Ge diode conducts at `0.3V`, both Ge and Si are in parallel, so `p.d.` across each is `0.3V`.
At `0.3V`, Si diode offers infinite resistance and it does not conduct.
`p.d.` across `R=5kOmega` is
`12-0.3=11.7V`
`V_(0)11.7V`
`i=(V_(0))/(R )=(11.7)/(5xx10^(3))=2.34mA`
When the connection of Ge diode are reversed, it will be in reverse biased and for conduction, the `p.d.` across the silicon diode will be `0.7V`
`p.d.` across `R=5kOmega` is
`12-0.7=11.3V`
`V_(0)=11.3V`
`i=(V_(0))/(R )=(11.3)/(5xx10^(3))=2.26mA`