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A transistor is connected in a common em...

A transistor is connected in a common emitter configuration.
The collector supply is 8 V and the voltage drop across a resistor of `800 Omega ` in
the collector circuit is 0.5 V. If the current gain factor `(alpha) ` is 0.96 , Find the base
current.

Text Solution

Verified by Experts

Given:`V_(cc)=8V, v_(0)=DeltaI_(c)R_(L)=0.5V, R_(L)=800Omega`
`alpha=0.96`
`beta=(alpha)/(1-alpha)=(0.96)/(1-0.96)=24`
`v_(0)=Delta_(C )R_(L)`
`0.5=DeltaI_(C )xx800impliesDeltaI_(C )=(0.5)/(800)A`
`beta=(DeltaI_(C ))/(DeltaI_(B)`
`DeltaI_(B)=(DeltaI_(C ))/(beta)=(0.5//800)/(24)=26xx10^(-6)A=26muA`
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