An `n-p-n` transistor is connected in common emiter configuration in which collector supply is `8V` and the boltage drop across the load resestance of `800Omega` connected in the collector circuit is `0.8V`. If current gain factor is `(25//26)`, determine the collector -emitter voltage and base current. if the internal resistance of the transistor is `200Omega`. calculate the voltage gain and power gain.

Explanation

`v_(0)=DeltaI_(C )R_(L)`
`0.8=DeltaI_(C )xx800impliesDeltaI_(C )=10^(-3)A`
`V_(CC)=8-0.8=7.2V`
`alpha=(25)/(26),beta=(alpha)/(1-alpha)=(25//26)/(1-25//26)=25`
`DeltaI_(B)=(DeltaI_(C ))/(beta)=(10^(-3))/(25)=4xx10^(-5)A=40muA`
`A_(v)=beta(R_(L))/(r_(i))=25xx(800)/(200)=100`
`A_(p)=beta^(2)(R_(L))/(r_(i))=betaA_(v)=25xx100=2500`