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A Ge specimen is dopped with Al. The con...

A `Ge` specimen is dopped with `Al`. The concentration of acceptor atoms is `~10^(21) at oms//m^(3)`. Given that the intrinsic concentration of electron hole pairs is `~10^(19)//m^(3)`, the concentration of electron in the speciman is

A

`10^(17)//m^(3)`

B

`10^(15)//m^(3)`

C

`10^(4)//m^(3)`

D

`10^(2)//m^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`n_(i)^(2)=n_(e)n_(h)`
`(10^(19))^(2)=n_(e)xx10^(21)`
`n_(e)=10^(17)//m^(3)`
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