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In a transistor, a change of 8.0mA in th...

In a transistor, a change of `8.0mA` in the emitter current produced a charge of `7.9mA` in the collector current. The base current changes by

A

`1muA`

B

`10muA`

C

`100muA`

D

`1000muA`

Text Solution

Verified by Experts

The correct Answer is:
C

`I_(E)=I_(B)+I_(C )`
`DeltaI_(E)=DeltaI_(B)+DeltaI_(c )`
`8=DeltaI_(B)+7.9`
`DeltaI_(B)=0.1 mA=0.1xx10^(-3)A=10^(-4)A =100xx10^(-6)A=100muA`
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CP SINGH-SEMICONDUCTORS-Exercises
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