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In the following common emitter configur...

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

A

`10mV`

B

`0.1V`

C

`1.0V`

D

`10V`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaI_(B)=(v_(i))/(R_(in))=(10^(-3))/(10^(3))=10^(-6)A`
`DeltaI_(c )=betaDeltaI_(B)=100xx10^(-6)=10^(-4)A`
`v_(0)=DeltaI-(c )R_(L)=10^(-4)xx10xx10^(3)=1V`
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