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A transistor is connected in common emmi...

A transistor is connected in common emmitter `(CE)` configuration. The collector supply is `8V` and the voltage deop across a resistor of `800 Omega` in the collector circuit is `0.8 V`. If the current gain factor `(alpha)` is `0.96`, then the change in base current is

A

`(1)/(24)mA`

B

`(1)/(12)mA`

C

`(1)/(6)mA`

D

`(1)/(3)mA`

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=0.96`
`beta=(alpha)/(1-alpha)=(0.96)/(1-0.96)=24`
`DeltaI_(c )=(0.8)/(8000=10^(-3)A`
`DeltaI_(B)=(deltaI_(c ))/(beta)=(10^(-3))/(24)A=(1)/(24)mA`
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