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The resonce frequency of the tank cuircu...

The resonce frequency of the tank cuircuit of an oscillator when `L=(1)/(pi^(2))mH` and `C=0.04 muF` are connected in parellel is

A

`250kHz`

B

`25kHz`

C

`2.5 kHz`

D

`25 MHz`

Text Solution

Verified by Experts

The correct Answer is:
B

`f=(1)/(2pi)sqrt((1)/(LC))`
`=(1)/(2pi)sqrt((1)/(10/(pi^(2))xx10^(-3)xx0.04xx10^(-6)))=(1)/(2xx2xx10^(-5))`
`=0.25xx10^(5)=25kHz`
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