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A wire carrying current I has the shape...

A wire carrying current `I` has the shape as shown in the adjoining figure. Linear parts of the wire are very long and parallel to X-axis while semicicular portion of radius `R` is lying in `Y-Z` plane. Magnetic field at point `O` is

A

`vec(B)=-(mu_(0))/(4pi) I/R(muhatixx2hatk)`

B

`vec(B)=-(mu_(0))/(4pi) I/R(pihati+2hatk)`

C

`vec(B)=(mu_(0))/(4pi) I/R(pihati-2hatk)`

D

`vec(B)=-(mu_(0))/(4pi) I/R(pihati+2hatk)`

Text Solution

Verified by Experts

The correct Answer is:
B


Magnetic field at `O`:
`vec(B)_(1)=(mu_(0)I)/(4piR)(-hatk)`
`vec(B)_(2)=(mu_(0)I)/(4R)(-hati)`
`vec(B)_(3)=(mu_(0)I)/(4piR)(-hatk)`
`vec(B)_(O)=vec(B)_(1)+vec(B)_(3)+vec(B)_(2)=(mu_(0)I)/(4piR)(-pi hati-2hatk)`
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