A conducting square frame of side `'a'` and a long straight wire carrying current `I` are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity `'V'`. The emf induced in the frame will be proportional to

Options

A. `1/((2x-a)^(2))`
B. `1/((2x+a)^(2))`
C. `1/((2x-a)(2x+a))`
D. `1/(x^(2))`

Answer

C

Explanation

`e=B_(1)Vl-B_(2)Vl`
`=[(mu_(0)I)/(2pi(x-a/2))-(mu_(0)I)/(2pi(x+a/2))] Vl`
`e prop1/((2x-a)(2x+a))`