Consider 3rd orbit of He^(+) (Helium) us...

Consider `3rd` orbit of `He^(+)` (Helium) using nonrelativistic approach the speed of electron in this orbit will be (given `K = 9 xx 10^(9)` constant `Z = 2` and `h` (Planck's constant) `= 6.6 xx 10^(-34)Js`.)

A

`1.46xx10^(6)m//s`

B

`0.73xx10^(6)m//s`

C

`3.0xx10^(8)`

D

`2.92xx10^(6)m//s`

Text Solution

Verified by Experts

The correct Answer is:

A

`v=2.2xx10^(6) Z/n m//s`
`=2.2xx10^(6)xx2/3`
`=1.46xx10^(6) m//s`

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