For a parallel beam of monochromatic light of wavelength `'lambda'` differaction is produced by a single slit whose width `'a'` is of the order as wavelength of the light. If `'D'` is the distance of the screen from the slit, the width of the central maxima will be

Options

A. `(Dlambda)/a`
B. `(Dlambda)/a`
C. `(2Da)/(lambda)`
D. `(2Dlambda)/a`

Answer

D

Explanation

Width of central maximum
`=(2D lambda)/a`