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A 2muF capacitor is charged as shown in ...

A `2muF` capacitor is charged as shown in the figure. The percentage of its stored energy disispated after the switch S is turned to poistion 2 is

A

`80%`

B

`0%`

C

`20%`

D

`75%`

Text Solution

Verified by Experts

The correct Answer is:
A

`("loss of energy")/("stored energy")=(1/2.(2xx8)/((2+8)) (V-0)^(2))/(1/(2).2.V^(2))=0.8`, i.e. `80%`
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