A sqaure loop `ABCD`, carrying a current `I_(2)` is placed near and coplanar with a long straight conductor `XY`, carrying a current `I_(1)` as shwon in Figure. The net force on the loop will be

Options

A. `(2mu_(0)Ii)/(3pi)`
B. `(mu_(0)Ii)/(2pi)`
C. `(mu_(0)Ii)/(2pi)`
D. `(2mu_(0)IiL)/(3pi)`

Answer

A

Explanation

`F_("net")=((mu_(0)Ii)/(2piL//2)-(mu_(0)Ii)/(2pi3L//2))L`
`=(2mu_(0)Ii)/(3pi)`