When an alpha-particle of mass 'm' movin...

When an `alpha-`particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on `m` as :

`m`

`1/m`

`1/(sqrt(m))`

`1/(m^(2))`

Text Solution

Verified by Experts

The correct Answer is:

`1/2 (mv^(2))/r=1/(4piepsilon_(O)).(Ze2e)/r`
`r prop 1//m`

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