An electron of mass `m` and a photon have same energy `E`. The ratio of de - Broglie wavelengths associated with them is :

Options

A. `1/C(E/(2m))^(1/2)`
B. `(E/(2m))^(1/2)`
C. `C(2mE)^(1/3)`
D. `1/(xC)((2m)/E)^(1/2)`

Answer

A

Explanation

`lambda_(e)=h/(sqrt(2mE)), lambda_(p)=(hc)/E`
`(lambda_(e))/(lambda_(p))=1/(sqrt(2mE)). E/C=1/C(E/(2m))^(1/2)`