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The de - Broglie wavelength of a neutron...

The de - Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature `T ("kelvin")` and mass `m`, is

A

`h/(sqrt(3mkT))`

B

`(2h)/(sqrt(3mkT))`

C

`(2h)/(sqrt(mkT))`

D

`h/(sqrt(mkT))`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda=h/(sqrt(2mk))=h/(sqrt(2m.3/2 kT))=h/(sqrt(3mkT))`
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