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Radioactive material 'A' has decay const...

Radioactive material 'A' has decay constant `'8 lamda'` and material 'B' has decay constant 'lamda'. Initial they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be `(1)/( e)` ?

A

`1/(7 lambda)`

B

`1/(8 lambda)`

C

`1/(9 lambda)`

D

`1/( lambda)`

Text Solution

Verified by Experts

The correct Answer is:
A

All option are wrong
`(N_(A))/(N_(B))=1/e=(N_(0)e^(-8lambdat))/(N_(0)e^(-lambdat))`
`t=1/(7lambda)`
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