[" Question "62],[" it: "sin^(2)" ."4cos^(2)B-cos^(2)A sin^(2)B=sin^(2)A-sin^(2)]

sin^(2)A cos^(2)B-cos^(2)A sin^(2)B=sin^(2)A-sin^(2)B

Prove that cos(A+B)cos(A-B)=cos^(2)A-sin^(2)B=cos^(2)B-sin^(2)A

Prove that sin ^(2) A cos ^(2) B+cos ^(2) A sin ^(2) B+cos ^(2) A cos ^(2) B+sin ^(2) A sin ^(2) B=1

sin ^ (2) A cos ^ (2) B + cos ^ (2) A sin ^ (2) B + sin ^ (2) A sin ^ (2) B + cos ^ (2) A cos ^ (2) B =

sin^(2) A cos^(2)B + cos ^(2) A sin^(2) B + sin^(2) A sin^(2) B+ cos^(2) A cos^(2) B=

Prove that sin(A+B)sin(A-B)=sin^(2)A-sin^(2)B=cos^(2)B-cos^(2)A

(i) (1)/(sin^(2)a)-(1)/(sin^(2)B)=(cos^(2) a-cos^(2) B)/(sin^(2)a*sin^(2) B)

If A-B=(2n+1)(pi)/(2) , n in Z ,then [[cos^(2)A,cos A sin A],[cos A sin A,sin^(2)A]][[cos^(2)B,cos B sin B],[cos B sin B,sin^(2)B]]=

Prove that sin (A+B) sin (A-B)=cos^(2) B-cos^(2) A

Prove that (cos A-cos B)^(2)+(sin A-sin B)^(2)=4sin^(2)((A-B)/(2))