The standard enthalpy change for the following reaction is 436.4 kJ :
`H_(2)(g)rarrH(g)+H(g)`
What is the `Delta_(f)H^(@)` of atomic hydrogen (H)?

Calculate the heat of reaction of the following reaction : CO_(2)(g) + H_(2)(g) rarr CO(g) + H_(2)O(g) Given that the Delta_(f)H^(@) of CO(g) = -110.5 kJ, Delta_(f)H^(@) of CO_(2)(g) = -393.8 kJ , Delta_(f)H^(@) of H_(2)O(g) = -241.8 kJ respectively

The standard enthalpy change for the reaction H_(2(g)) rarr H_((g)) + H_((g)) is + 436.4 kj mol^(-1) . Calculate standard enthalpy of formation of atomic hydrogen.

The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

Calculate the bond enthalpy of the O - H bond using the following thermochemical equations: H_(2) O (g) rarr H (g) + OH (g) , Delta_(bond H^(@) = 502 kJ OH (g) rarr (g) + O (g), Delta_(bond) H^(@) = 427 kJ

For the reaction, 2H_(2)O(g) rarr 2H_(2)(g) + O_(2)(g), Delta H = 571.6 kJ Delta_(f) H^(theta) of water is: