[11x^(2)-x+1=0],[-13,x^(2)-8x+1=0]

If alpha,beta are the roots of the equation 2x^(2)+4x-5=0, the equation whose roots are the reciprocals of 2 alpha-3 and 2 beta-3 is - (i) x^(2)+10x-11=0 (ii) 11x^(2)+10x+1=0 (ii) x^(2)+10x+11=0 (iv) 11x^(2)-10x+1=0

(2x^(2)+8x^(3)+11x-12)-(-5x^(2)-2x-13x^(3)-2)+(-4+2x-3x^(2)-5x^(3))

Find the value of x if, /_\ = |[x^(2),1,x],[0,3,-1],[x,-1,1]|=0

Let 2f(x^(2))+3f(11x^(2))=x^(2)-1 for all x in R=[0], Then f(x) equals

If x^(2)-8x+13 = 0, x =

Simplify the following : 5x^(4) - 7x^(2) +8x - 1 +3x^(2) - 9x^(2) + 7 - 3x^(4)+11x - 2 +8x^(2)

The locus of a point "P" ,if the join of the points (2,3) and (-1,5) subtends right angle at "P" is x^(2)+y^(2)-x-8y+13=0 x^(2)-y^(2)-x+8y+3=0 x^(2)+y^(2)-4x-4y=0,(x,y)!=(0,4)&(4,0) x^(2)+y^(2)-x-8y+13=0,(x,y)!=(2,3)&(-1,5)