The inner diameter of a breass ring 273 ...

The inner diameter of a breass ring `273 K` is `5 cm`. To what temperature should it be heated for it to accommodate a ball `5.01 cm` in diameter. `(alpha = 10^(-5//@)C)`

`273 K`

`372 K`

`437 K`

`173 K`

Text Solution

Verified by Experts

The correct Answer is:

`Deltat = (r_(2) - r_(1))/(r_(1)alpha)`

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