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A Fahrenheit thermometer registers 100^(...

A Fahrenheit thermometer registers `100^(@)F` while a faulty Celsius thermometer registers `44^(@)C`. Find the error in the later

A

`0.37^(@)`

B

`0.87^(@)`

C

`0.67^(@)`

D

`0.48^(@)`

Text Solution

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The correct Answer is:
To find the error in the faulty Celsius thermometer that registers \(44^\circ C\) while the Fahrenheit thermometer registers \(100^\circ F\), we will follow these steps: ### Step 1: Convert Fahrenheit to Celsius We will use the formula to convert the temperature from Fahrenheit to Celsius: \[ T_C = \frac{5}{9} (T_F - 32) \] where \(T_C\) is the temperature in Celsius and \(T_F\) is the temperature in Fahrenheit. Given \(T_F = 100^\circ F\), we can substitute this value into the formula. ### Step 2: Substitute the Fahrenheit value Substituting \(T_F = 100\) into the formula: \[ T_C = \frac{5}{9} (100 - 32) \] ### Step 3: Calculate the difference Now, calculate \(100 - 32\): \[ 100 - 32 = 68 \] ### Step 4: Multiply by \(\frac{5}{9}\) Now we will multiply \(68\) by \(\frac{5}{9}\): \[ T_C = \frac{5}{9} \times 68 \] ### Step 5: Perform the multiplication Calculating \(\frac{5 \times 68}{9}\): \[ T_C = \frac{340}{9} \approx 37.78^\circ C \] ### Step 6: Determine the error Now, we need to find the error in the faulty Celsius thermometer. The faulty thermometer reads \(44^\circ C\), while the correct value we calculated is approximately \(37.78^\circ C\). To find the error: \[ \text{Error} = \text{Faulty Reading} - \text{Correct Reading} \] Substituting the values: \[ \text{Error} = 44 - 37.78 \] ### Step 7: Calculate the error Now, perform the subtraction: \[ \text{Error} = 6.22^\circ C \] ### Final Result The error in the faulty Celsius thermometer is \(6.22^\circ C\). ---

To find the error in the faulty Celsius thermometer that registers \(44^\circ C\) while the Fahrenheit thermometer registers \(100^\circ F\), we will follow these steps: ### Step 1: Convert Fahrenheit to Celsius We will use the formula to convert the temperature from Fahrenheit to Celsius: \[ T_C = \frac{5}{9} (T_F - 32) \] ...
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