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When the temperature of a rod increases ...

When the temperature of a rod increases from t to `r+Delta t`, its moment of inertia increases from I to `I+Delta I`. If `alpha` is the value of `Delta I//I` is

A

`Delta t//t`

B

`Delta t//t`

C

`alpha Delta t`

D

`2alpha Delta t`

Text Solution

Verified by Experts

The correct Answer is:
D
from `I = MR^(2), (DeltaI)/(I) = 2 xx (DeltaR)/(R), (DeltaI)/(I) = 2alphaDeltat`
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