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A pendulum clock gives correct time at 2...

A pendulum clock gives correct time at `20^(@)C` at a place where `g= 10m//s^(2)`. The pendulum consists of a light steel rod connected to a heavy ball. If it is taken to a different place where `g = 10.01m//s^(2)` at what temperature the pendulum gives correct time ( `alpha` of steel of `10^(-5//@)C`)

A

`30^(@)C`

B

`60^(@)C`

C

`100^(@)C`

D

`120^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`(Deltal)/(l) = (Deltag)/(g) = alphaDeltat`
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