The graph between two temperature scales `A` and `B` is shown in Fig. Between upper fixed point and lower fixed point there are `150` equal divisions on scales `A` and `100` on scale `B`. The relation between the temperature in two scales is given by_

Options

A. `(t_(A) - 180)/(100) = (t_(B))/(150)`
B. `(t_(A) - 30)/(150) = (t_(B))/(100)`
C. `(t_(B) - 180)/(150) = (t_(A))/(100)`
D. `(t_(B ) - 40)/(100) = (t_(A))/(180)`

Answer

B

Explanation

`("Reading on any scale" - LFP)/(UFP - LFP) ="Constant"`