On a hypothetical scale `X`, the ice point is `40^(@)` and the steam point is `120^(@)`. For another scale `Y` the ice point and steam points are `-30^(@)` and `130^(@)` respectively. If `X`-reads `50^(@)` The reading of `Y` is

Options

A. `-5^(@)`
B. `-8^(@)`
C. `-10^(@)`
D. `-12^(@)`

Answer

C

Explanation

`("Reading"-LFP)/(UFP-LFP)="constant," (120-x)/(80)=(130-y)/(160)`