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If a cylinder of diameter 1.0cm at 30^(@...

If a cylinder of diameter `1.0cm` at `30^(@)C` is to be slid into a hole of diameter `0.9997 cm` in a steel plate at the same temperature, the minimum required rise in the temperature of the plate is: (Coefficient of linear expansion of steel`= 12 xx 10^(-6//@)C`)

A

`25^(@)C`

B

`35^(@)C`

C

`45^(@)C`

D

`55^(@)C`

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the minimum required rise in temperature of the steel plate so that the diameter of the hole expands enough to accommodate the cylinder. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Diameter of the cylinder, \( D_c = 1.0 \, \text{cm} = 0.01 \, \text{m} \) - Diameter of the hole, \( D_h = 0.9997 \, \text{cm} = 0.009997 \, \text{m} \) - Initial temperature, \( T_1 = 30^\circ C \) - Coefficient of linear expansion of steel, \( \alpha = 12 \times 10^{-6} \, \text{°C}^{-1} \) 2. **Determine the Required Expansion:** - The hole needs to expand from \( D_h \) to \( D_c \). - The required expansion in diameter, \( \Delta D = D_c - D_h = 0.01 \, \text{m} - 0.009997 \, \text{m} = 0.0003 \, \text{m} \). 3. **Use the Linear Expansion Formula:** - The formula for linear expansion is given by: \[ L_2 = L_1 (1 + \alpha T) \] - Here, \( L_1 \) is the initial diameter of the hole, and \( L_2 \) is the final diameter after expansion. We can set \( L_2 = D_c \) and \( L_1 = D_h \). 4. **Set Up the Equation:** - Plugging in the values: \[ D_c = D_h (1 + \alpha T) \] - Rearranging gives: \[ 1 = \frac{D_h}{D_c} (1 + \alpha T) \] 5. **Substituting Values:** - Substitute \( D_h = 0.009997 \, \text{m} \) and \( D_c = 0.01 \, \text{m} \): \[ 1 = \frac{0.009997}{0.01} (1 + 12 \times 10^{-6} T) \] - This simplifies to: \[ 1 = 0.9997 (1 + 12 \times 10^{-6} T) \] 6. **Solving for \( T \):** - Expanding the equation: \[ 1 = 0.9997 + 0.9997 \times 12 \times 10^{-6} T \] - Rearranging gives: \[ 1 - 0.9997 = 0.9997 \times 12 \times 10^{-6} T \] - Thus: \[ 0.0003 = 0.9997 \times 12 \times 10^{-6} T \] - Solving for \( T \): \[ T = \frac{0.0003}{0.9997 \times 12 \times 10^{-6}} \approx 25.0 \, \text{°C} \] ### Conclusion: The minimum required rise in the temperature of the plate is approximately \( 25.0 \, \text{°C} \).

To solve the problem, we need to determine the minimum required rise in temperature of the steel plate so that the diameter of the hole expands enough to accommodate the cylinder. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Diameter of the cylinder, \( D_c = 1.0 \, \text{cm} = 0.01 \, \text{m} \) - Diameter of the hole, \( D_h = 0.9997 \, \text{cm} = 0.009997 \, \text{m} \) - Initial temperature, \( T_1 = 30^\circ C \) ...
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