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A second's pendulum clock has a steel wi...

A second's pendulum clock has a steel wire. The clock is calibrated at `20^@ C`. How much time does the clock lose or gain in one week when the temperature is increased to `30^@ C` ? `alpha_(steel = 1.2 xx 10^-5(^@ C)^-1`.

A

`0.3628s`

B

`3.626s`

C

`362.8 s`

D

`36.28s`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaT(1)/(2)alphaDeltatxx7xx86400`
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