A wooden block of density `860 kg//m^(3)` at `0^(@)C` is floating on bezene liquid of density `900 kg/m^(3)` at `0^(@)C`. The temperature at which the block just submerge in benzene is
`[gamma_(wo od)=8xx10^(-5//@)c, gamma_("benzene")=12xx10^(-4//@)c]`

Options

A. `24^(@)c`
B. `42^(@)c`
C. `16^(@)c`
D. `32^(@)c`

Answer

B

Explanation

If the boat sinks in benzene
`V_(B)d_(B)g = V_(l)d_(l)g , V_(B)d_(B) = V_(l)d_(l)`
`d_(("wood"))` at `t^(0)C = d_(("benzene"))` at `t^(0)C`
`((d_(0))_("wood"))/((1 + gamma_(w)Deltat)) = ((d_(0))_("benzene"))/((1 + gamma_(B)Deltat))`