The co-efficient of linear expansion of iron is `11//180` of volume coefficient of expansion of mercury which is `18 xx 10^(-5) // ^(0)C`. An iron rod is `10m` long at `27^(@)C`. The length of the rod will be decreased by `1.1mm` then the termperature the rod changes by

Options

A. `0^(@)C`
B. `10^(@)C`
C. `20^(@)C`
D. `170^(@)C`

Answer

B

Explanation

`alpha_(iron) = (11)/(800)gamma_(Hg) , Deltal = lalphaDeltat`