The loss of weight of a solid when immersed in a liquid at `0^(@)C` is `W_(0)` and at `t^(@)C` is `'W'`. If cubical coefficient of expansion of the solid and the liquid are `gamma_(s)` and `gamma_(1)` then `W =`

Options

A. `W_(0)[1 + (gamma_(s) - gamma_(l))t]`
B. `W_(0)[1 - (gamma_(s) - gamma_(l))t]`
C. `W_(0)[1 + (gamma_(l) - gamma_(s))t]`
D. `W_(0)[1 - (gamma_(l) - gamma_(s))t]`

Answer

A, D

Explanation

`W_(0) = V_(0)d_(o)g, W_(t) = V_(t)d_(t)g`
`(W_(0))/(W_(t)) = (V_(0)d_(0))/(V_(t)d_(t)) = (V_(0)d_(0)[1 + gamma_(l)t])/(V_(0)[1 + gamma_(s)t]d_(t))`